In the case of d-d transition taking place from $t_{2 g}$ to e_g orbitals in a transition metal ion having $d^{2}$ configuration, the correct statement is

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The excited electron goes to $d_{x^{2} - y^{2}}$ orbital in e_g set while the other electron remain in $d_{x y}$ orbital of $t_{2 g}$ set

The excited electron goes to $d_{z^{2}}$ orbital in e_g set while the other electron remain in $d_{x y}$ orbital of $t_{2 g}$ set

The excited electron goes to any one of the d-orbital in e_g set while the other electron remain in one of the d-orbital in $t_{2 g}$ set

The excited electron goes into $d_{z^{2}}$ orbital of e_g set while the other electron remain in either $d_{y z}$ or $d_{x z}$ orbital of $t_{2 g}$ set

answer is B.

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Detailed Solution

When the two electrons are present in $d_{x y}$ and $d_{z^{2}}$ gives minimum repulsion and maximum stability due to $90^{0}$ angle. All the other arrangements give more repulsion due lesser angle of $45^{0}$

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