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In the case of interference , the maximum and minimum intensities are in the ratio $25 : 4$ . Then

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The maximum and minimum amplitudes will be in the ratio $9 : 5$

The amplitude of the individual waves will be in the ratio $4 : 1$

The amplitude of the individual waves will be in the ratio $7 : 3$

The intensities of the individual waves will be in the ratio $4 : 3$

answer is C.

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Detailed Solution

$\frac{I_{\max}}{I_{\min}} = \frac{25}{4} = \frac{{A^{2}}_{\max}}{{A^{2}}_{\min}}$

$\frac{A_{\max}}{A_{\min}} = \frac{5}{2}$

$\Rightarrow \frac{A_{1} + A_{2}}{A_{1} - A_{2}} = \frac{5}{2} \Rightarrow \frac{A_{1}}{A_{2}} = \frac{7}{3} S o, \frac{I_{1}}{I_{2}} = {(\frac{A_{1}}{A_{2}})}^{2} = \frac{49}{9}$

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