In the case of interference, the maximum and minimum intensities are in the ratio 16:9. Then

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The maximum and minimum amplitudes will be in the ratio 9 : 5

The amplitudes of the individual waves will be in the ratio 4:1

The amplitudes of the individual waves will be in the ratio 7 : 1

The intensities of the individual waves will be in the ratio 4 : 3

answer is C.

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Detailed Solution

$\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{{16}}{9} \Rightarrow \$ $\frac{\left ( A_1+A_2 \right )^2}{\left ( A_1-A_2 \right )^2}=\frac{16}{9}$

$\frac{{{A_1} + {A_2}}}{{{A_1} - {A_2}}} = \frac{{{A_{\max }}}}{{{A_{\min }}}} = \frac{4}{3} \Rightarrow \frac{{{A_1}}}{{{A_2}}} = \frac{{4 + 3}}{{4 - 3}} = \frac{7}{1}$

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