In the chemical reaction ${Cl}_{2} + H_{2} S \to 2 HCl + S,$ the oxidation number of sulphur changes from

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-2 to -1

-2 to 0

2 to 0

0 to 2

answer is B.

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Detailed Solution

Oxidation state of Sulphur in $H_{2} S is - 2,$ while it is zero in ‘S’, i.e., in this reaction oxidation of Sulphur and reduction of chlorine is takes place.

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