In the circuit, all capacitor are identical, each of capacity 2µF and they are infinite in number. If AB is connected to a battery of 10V then the charge drawn from the battery is

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10µC

5µC

40µC

20µC

answer is A.

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Detailed Solution

$\begin{array}{l} C_{P} = C + \frac{C}{2} + \frac{C}{4} + \frac{C}{8} + \dots C_{P} = C [\frac{1}{1 - 1 / 2}] = 2 C \\ C_{P} = 2 \times 2 = 4 μF \\ Q = C_{P} \times V = 4 \times 10^{- 6} \times 10 = 40 μC \end{array}$

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