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Q.

In the circuit as shown. $C = 1 F, L = 11 H .$ Charge in the capacitor is 4C at time $t = 0$ and it is decreasing at the rate of $\sqrt{3} C / s$ . Find the maximum charge $(i n C)$ in the capacitor.

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Detailed Solution

$i = - \frac{d q}{d t} = \sqrt{3} c / s$

and $\frac{1}{2} \frac{{q^{2}}_{\max}}{C} = \frac{1}{2} \frac{q^{2}}{C} + \frac{1}{2} L i^{2}$

$q_{\max} = {[q^{2} + L C i^{2}]}^{1 / 2} = 7 C$

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In the circuit as shown. C=1F,L=11H. Charge in the capacitor is 4C at time t=0 and it is decreasing at the rate of 3 C/s. Find the maximum charge (in C) in the capacitor.