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time constant is $\frac{L}{R}$

time constant is $\frac{2 L}{R}$

steady state current in inductor is $\frac{2 E}{R}$

steady state current in inductor is $\frac{E}{R}$

answer is A, B.

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Detailed Solution

Calculate the time constant

Battery is replaced by a wire
$τ = \frac{L}{R_{ab}} = \frac{L}{R} a n d i = \frac{E}{R / 2}$

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