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In the circuit figure treat the diode as a ideal . Then current in the $8 Ω$ resistor is

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40 A

5 A

2 A

7 A

answer is C.

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$W i t h b a t t e r y p o l a r i t y, D 1 i s i n f o r w a r d b i a s a n d D 2 i s i n r e v e r s e b i a s . S o, 4 Ω a n d 8 Ω a r e i n s e r i e s . A s p e r O h m' s L a w, I = \frac{24}{4 + 8} = 2 A$

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