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In the circuit given here, the points A, B and C are 70V, zero, 10V respectively then

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The point D will be at a potential of 60V

The point D will be at a potential of 20V

Currents in the paths AD, DB and DC are in the ratio of 1 : 2 : 3

Currents in the paths AD, DB and DC are in the ratio of 3 : 2 : 1

answer is D.

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Detailed Solution

$\frac{70 - V_{D}}{10} = \frac{V_{D} - 0}{20} + \frac{V_{D} - 10}{30}$

$\Rightarrow V_{D} = 40 V$

$i_{A D} : i_{D B} : i_{D C} = 3 : 2 : 1$

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