In the circuit R₁ = 400 ohm and R₂= 200 ohm. If the resistance of the voltmeter R =10,000 ohm, voltmeter reading is

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greater than 3V

greater

less than 2V

answer is D.

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Detailed Solution

Since, resistance of voltmeter >>> R₂, it can be neglected.

$∴ R_{1}, R_{2}$ are in series.

Current in circuit will be

$i = \frac{E}{R_{1} + R_{2}} = \frac{6}{200 + 400} = 0.01 A$

Voltage across R₂ is

$V = i R_{2} = 0.01 \times 200 = 2 V$

Due to the presence of voltmeter resistance parallel to R₂, there could be slight decrease in this voltage.

So, $V < 2 v$

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