In the circuit shown a current through 20$\Omega$ resistor equals

Let x be the current through 20 $\Omega$ resistor and y be the current through 10 $\Omega$ resistor. 

Applying KVL, $10-10\mathrm{y}=0\Rightarrow \mathrm{y}=1 \mathrm{A}$

Also, $20-20\mathrm{x}+10\mathrm{y}=0\Rightarrow 20-20\mathrm{x}+10\times 1=0\Rightarrow \mathrm{x}=3/2 \mathrm{A}$