In the circuit shown, a potential difference of $100 V$ is applied across $A B$ . Then

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The potential difference between points $C$ and $D$ is $50 V$

All the capacitors have equal charge

The potential difference between $B a n d D i s - 25 V$

The potential difference between $A a n d C$ is $25 V$

answer is A, B, C.

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Detailed Solution

Equivalent capacitance between A and B , $C_{A B} = \frac{3 C}{2} . C h a r g e s u p p l i e d t o t h e s y s t e m = \frac{3 C V}{2} Q_{1} = C h a r g e o n t h e c a p a c i t o r b e t w e e n A a n d B = \frac{C}{3 C / 2} \times \frac{3 C V}{2} = C v Q_{2} = C h a r g e o n t h e c a p a c i t o r b e t w e e n C a n d D = \frac{3 C V}{2} - C V = \frac{C V}{2} T h e r e f o r e V_{C} - V_{D} = \frac{Q_{2}}{C} = \frac{V}{2} = 50 V a n d V_{A} - V_{C} = \frac{Q_{1}}{2 C} = 25 V a l s o V_{B} - V_{D} = - 25 V$