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Q.

In the circuit shown below, the ac source has voltage V=20 cos(ωt) volts with  ω= 2000 rad/sec. the amplitude of the current will be nearest to  

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a

2/5A

b

5A

c

2A

d

3.3 A

answer is A.

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Detailed Solution

R=6+4=10 Ω 
 XL=ωL=2000×5×10−3=10 Ω
 XC=1ωC=12000×50×10−6=10 Ω
 ∴  Z=R2+(XL−XC)2=10 Ω
Amplitude of current =i0=V0Z=2010=2A

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