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In the circuit shown below the AC source has voltage $V = 20 \cos ω t$ volt with $ω = 2000 r a d / s$ the amplitude of the current will be nearest to

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3.3A

$\frac{2}{\sqrt{5}} A$

$\sqrt{5} A$

answer is A.

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Detailed Solution

$z = \sqrt{R^{2} + {(ω L - \frac{1}{ω C})}^{2}}$

$= 10 Ω i = \frac{V_{0}}{z} = \frac{20}{10} = 2 A$

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