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In the circuit shown (Fig). if the diode forward voltage drop is 0.3V, the voltage difference between A and B is :

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0.5V

2.3V

1.3V

answer is B.

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Detailed Solution

$\begin{array}{l} - 0 .2 \times 10^{- 3} \times 5 \times 10^{3} - V_{B} = 0 \\ \Rightarrow V_{A} - V_{B} = 2 .3 volt \end{array}$

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