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Q.

In the circuit shown in Fig. the cell is ideal, with e.m.f. = 2V. The resistance of the coil of the galvanometer G is 1 $Ω$ . Then

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a

Potential difference across C₂ is 1.2 V

b

Potential difference across C₁ is 1V

c

No current flows in G

d

0.2 A current flows in G

answer is B, C, D.

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Detailed Solution

Current through resistances remains constant .

$I_{g} = \frac{2}{(4 + 5)} A = 0.2 A$

$V_{c_{1}} = 4 \times \frac{2}{9} V = 0.88 v o l t$ $≃ 1 v o l t$

$V_{c_{2}} = 5 \times \frac{2}{9} v o l t = 1.2 v o l t$

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