In the circuit shown in Fig. , the charge on the $5 \mathrm{\mu F}$ capacitor will be

 

Potential difference across upper branch is 6 V.

$V_2=V\left(\frac{C_1}{C_1+C_2}\right)=10\left[\frac{3}{3+7}\right]=3V$.

Hence, potential difference across $5 \mathrm{\mu F}$ capacitor is 3 V. Thus, charge in $5 \mathrm{\mu F}$ capacitor is $5\times 3=15 \mu C$.