In the circuit shown in figure, $C_{1} = 1 μ F$ and $C_{2} = 2 μ F$ . Capacitor $C_{1}$ is charged to 100 V and $C_{2}$ is charged to 20 V. After charging they are connected as shown.

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When $S_{1}$ is closed, no charge flows through $S_{1}$

When $S_{1}$ and $S_{2}$ are closed together, no charge flows through the switch $S_{1}$

When all the three switches are closed, $80 μ C$ charge flows through the switch $S_{1}$

When all the three switches are closed, both the capacitors lose energy

answer is A, B, C.

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Detailed Solution

Charge will flow only when the circuit is closed, $i . e .,$ all keys are closed.
Initial charges $q_{1} = 100 μ C$ and $q_{2} = 80 μ C$
If a charge q flows anticlockwise, new charges are $q_{1}' = 100 - q$ and $q_{2}' = 40 - q$
$K V L \frac{100 - q}{1} + \frac{40 - q}{2} = 0 \Rightarrow q = 80 μ C$
$\Rightarrow$ New charges are $20 μ C$ and $- 40 μ C$ capacitor $C_{2}$ does not lose energy finally