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Q.

In the circuit shown in figure initially key K1 is closed and key K2 is open. Then, K1 is opened and K2 is closed (order is important). 

[Take Q'1 and Q'2 as charges on C1 and C2 and V1 and V2 as voltage, respectively.] 

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Then,

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a

charge on C1 gets redistributed such that Q'1 = Q'2

b

charge on C1 gets redistributed such that V1 = V2

c

charge on C1 gets redistributed such that Q'1 + Q'2 = Q

d

charge on C1 gets redistributed such that C1V1 + C2V2 =C1E

answer is A, C, D.

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Detailed Solution

The charge stored by capacitor C1 gets redistributed between C1 and C2 till their potentials become same, i.e. V2 = V1. By law of conservation of charge, the charge stored in capacitor C1 when key K1 is closed and key K2 is open is equal to sum of charges on capacitors C1 and C2 when K1 is opened and K2 is closed, i.e., Q'1 + Q'2 =Q.

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In the circuit shown in figure initially key K1 is closed and key K2 is open. Then, K1 is opened and K2 is closed (order is important). [Take Q'1 and Q'2 as charges on C1 and C2 and V1 and V2 as voltage, respectively.] Then,