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In the circuit shown in figure neglecting source resistance the voltmeter and ammeter reading will respectively, be

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0V, 3A

150V, 3A

150V, 6A

0V, 8A

answer is D.

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Detailed Solution

The voltage V_L and V_C are equal and opposite so voltmeter reading will be zero.

$Also\,\,R = 30\,\Omega ,\,\,{X_L} = {X_C} = 25\Omega$

$i=\frac{v}{\sqrt{R^2+{(X_L-X_C)^2}}}=\frac{v}{R}=\frac{240}{30}=8\,\,A$

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