In the circuit shown in figure, the voltmeter and ammeter reading will, respectively, be

Since XL = X_C, the voltage V_L and V_C are equal and opposite. So voltmeter reading will be zero.

Also, $\mathrm{R}=30 \mathrm{\Omega }, {\mathrm{X}}_{\mathrm{L}}={\mathrm{X}}_{\mathrm{C}}=25 \mathrm{\Omega }$

So, $\mathrm{i}=\frac{\mathrm{V}}{\sqrt{{\mathrm{R}}^2+{\left({\mathrm{X}}_{\mathrm{L}}-{\mathrm{X}}_{\mathrm{C}}\right)}^2}}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{240}{30}=8 \mathrm{A}$