In the circuit shown in figure, $C_1=C_2=2\mu F$. In steady state, the charge stored in

In staedy state,current through each branch  is $\frac{120}{6}A i.e. 20 A.$ The potential difference across $C_1$ is $(2\times 20-1\times 20) V i.e.20V$ and potential difference across $C_2$ is ( 3$\times 20 - 3\times 20 ) V i.e.$ $0V$. Then charge stored on $C_1$ is $40\mu C$ and charge stored on $C_2$ is $0\mu C$