In the circuit shown in figure, C1=C2=2μF. In steady state, the charge stored in

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In the circuit shown in figure, $C_{1} = C_{2} = 2 μ F$ . In steady state, the charge stored in

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capacitor $C_{2}$ is zero

both capacitors are zero

capacitor $C_{1}$ is $40 μ C$

capacitor $C_{1}$ is zero

answer is B, D.

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Detailed Solution

In staedy state,current through each branch is $\frac{120}{6} A i . e . 20 A .$ The potential difference across $C_{1}$ is $(2 \times 20 - 1 \times 20) V i . e . 20 V$ and potential difference across $C_{2}$ is ( 3 $\times 20 - 3 \times 20) V i . e .$ $0 V$ . Then charge stored on $C_{1}$ is $40 μ C$ and charge stored on $C_{2}$ is $0 μ C$