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In the circuit shown in the figure, in steady state

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The charge in 10 $μ$ Fcapacitor is 40 $μ$ C.

The charge in 4 $μ$ Fcapacitor is 32 $μ$ C.

The charge in 5 $μ$ Fcapacitor is 30 $μ$ C.

The current drawn from the battery is 1A.

answer is A, B, C, D.

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Detailed Solution

Charge in 5 $μ$ F capacitor = 5 × 6 = 30 $μ$ C

Charge in 10 $μ$ F capacitor = 10 × 4 = 40 $μ$ C

Charge in 4 $μ$ F capacitor = 4 × 8 = 32 $μ$ C

$i = \frac{10}{4 + 2 + 2 + 2} = 1 A$

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