In the circuit shown in the figure, reading of voltmeter is $V_{1}$ when only $S_{1}$ is closed, reading of voltmeter is $V_{2}$ when only $S_{2}$ is closed and reading of voltmeter is $V_{3}$ when both $S_{1} and S_{2}$ are closed. Then,

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$V_{2} > V_{1} > V_{3}$

$V_{3} > V_{1} > V_{2}$

$V_{1} > V_{2} > V_{3}$

$V_{3} > V_{2} > V_{1}$

answer is B.

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Detailed Solution

In series P.D is directly proportional to ‘R’
When $S_{1}$ is closed $V_{1} = \frac{3 v}{4} (1 : 3)$
When $S_{2}$ is closed $V_{2} = \frac{6 v}{7} (1 : 6)$
When both are closed $V_{3} = \frac{2 v}{3} (1 : 2)$
$V_{2} > V_{1} > V_{3}$

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