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In the circuit shown in the figure, the ac source gives a voltage $V = 20 \cos (2000 t)$ Neglecting source resistance, the voltmeter and ammeter reading will be

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0V,0.47 A

1.68V, 0.47 A

0 V, 1.4 A

5.6 V, 1.4 A

answer is D.

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Detailed Solution

$Z = \sqrt{{(R)}^{2} + {(X_{L} - X_{C})}^{2};}$

$R = 10 Ω, X_{L} = ω L = 2000 \times 5 \times 10^{- 3} = 10 Ω$

$X_{C} = \frac{1}{ω C} = \frac{1}{2000 \times 50 \times 10^{- 6}} = 10 Ω$ i.e $Z = 10 Ω$

Maximum current $i_{0} = \frac{V_{0}}{Z} = \frac{20}{10} = 2 A$

Hence $i_{r m s} = \frac{2}{\sqrt{2}} = 1.4 A$

And $V_{r m s} = 4 \times 1.41 = 5.64 V$

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