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In the circuit shown in the figure, the ammeter shows 5A current, voltmeter shows 250V and the internal resistance of the voltmeter is 2500Ω, then the value of R is

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150Ω

0.51Ω

510Ω

51Ω

answer is D.

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Detailed Solution

Equivalent resistance of R and r(internal resistance of voltmeter) connected parallel will be :

$R_{eq} = \frac{2500 R}{2500 + R}$

Hence, from Ohm's law :

$V = 250 = 5 (\frac{2500 R}{2500 + R})$

$R = \frac{2500}{49} Ω \approx 51 Ω$

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