In the circuit shown in the figure, the current through

Equivalent resistance of the circuit  R = 9 Ω

$\therefore \text{ Main current }\mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{9}{9}=1\mathrm{A}$

After proper distribution, the current through 4 Ω resistance is 0.25 A.