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Q.

In the circuit shown in the figure, the switch S is in position 1 for a long time. Now the switch is thrown to position 2. Find the total heat developed in the circuit till the steady state is reached again

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a

0.04 J

b

0.4 J

c

0.02 J

d

0.2 J

answer is A.

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Detailed Solution

Initial charge on capacitor: $Q_{1} = 2 \times 100 = 200 μ C$

Final charge: $Q_{2} = 2 \times 300 = 600 μ C$

$W_{b} = 300 [Q_{2} - Q_{1}] = 12, 000 μ J$

$Δ U = \frac{1}{2} C [300^{2} - 100^{2}] = 80000 μ J$

Heat $= W_{b} - Δ U = 40000 μ J = 0.04 J$

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In the circuit shown in the figure, the switch S is in position 1 for a long time. Now the switch is thrown to position 2. Find the total heat developed in the circuit till the steady state is reached again