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In the circuit shown in the figure, the total charge is $750 μC$ and the voltage across capacitor $C_{2}$ is 20 V. Then the charge on capacitor C₂ is:

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$590 μC$

$160 μC$

$450 μC$

$650 μC$

answer is A.

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Detailed Solution

$\begin{array}{l} Q = C_{1} V_{1} \Rightarrow 750 = 15 V_{1} \Rightarrow V_{1} = 50 V, V_{2} = 20 V \\ Q_{3} = C_{3} V_{2} = 160 μc \\ Q_{2} = 750 - 160 = 590 μc \end{array}$

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