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In the circuit shown, the diodes X and Y are ideal and a battery of 10 V can be connected between the terminals A and B. The minimum and maximum currents sent by the battery will be respectively

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$0.4 A, 0.1 A$

$0.1 A, 0.4 A$

$1 / 9 A, 2 / 3 A$

$2 / 3 A, 1 / 9 A$

answer is B.

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Detailed Solution

When A is +ve and B is –ve, no current will flow in the branch containing Y. The current now will be 10/(10+90) =0.1A.
In the second case with A –ve and B +ve, no current in branch containing X. The current now will be 10/(10+15)=0.4A

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