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Q.

In the circuit shown, the switch S has been closed for a long time. At time t= 0, the switch is opened. It remains open for a long time T, after which it is closed again.

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a

voltage drop across 100kΩ  resister is  20et/1.53V for t < T 

b

voltage drop across 100kΩ  resister is 10(eTte(T3t)/3) for  t>T

c

voltage drop across  100kΩ resister is  10et/1.5V for t<T

d

The time constant of the circuit is 1.5sec for t > T 

answer is B.

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Detailed Solution

When the switch ‘S’ is opened,
τ=RC=1.5sec
Voltage across the capacitor,
Vc=10(1et/1.5) for t<T
The current,  i=dQdt=CdVcdt
=2003×106(et/1.5) for t<T
Voltage drop across 100 k μ  resister,
 for t < T
After t = T,

τ=100kΩ×10μF=1sec

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In the circuit shown, the switch S has been closed for a long time. At time t= 0, the switch is opened. It remains open for a long time T, after which it is closed again.