In the circuit shown there is steady state with the switch(s) closed. The switch is opened at t = 0. Choose the correct option(s).
(Given : $ε = 24 V,$ $C_{1} = 3 F$ and $C_{2} = 2 F$ )

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The voltage across $C_{2}$ before the switch is open, is 8 V

The voltage across $C_{2}$ after a long time after the switch is open, is 24 V

The voltage across $C_{1}$ before the switch is open, is 12 V

The voltage across $C_{1}$ after a long time after the switch is open, is 12 V

answer is A, C, D.

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Detailed Solution

$i = \frac{24}{3 + 9 + 6} = \frac{4}{3} A V_{1} = \frac{4}{3} \times 9 = 12 V$

$V_{2} = \frac{4}{3} \times 6 = 8 V A t t = \infty$

$V_{2} = V_{1} = 24$

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