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In the circuit the current through Zener diode is $(V_{Z} = 10 V)$

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5 mA

10 mA

6.67 mA

3.33 A

answer is D.

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Detailed Solution

The current through $R_{2}$ is

$I_{2} = \frac{V_{1}}{R_{2}} = \frac{10}{1500} = 6.67 \times 10^{- 3} A = 6.67 m A$

The current through $R_{2}$ is

$I_{1} = \frac{V_{1}}{R_{1}} = \frac{(V - V_{Z})}{R_{1}} = \frac{15 - 10}{500} = \frac{5}{500} = 10 m A$

$∴$ The current through Zener diode is

$I_{Z} = I_{1} - I_{2} = 10 - 6.67 = 3.33 m A$

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