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In the complete combustion of butanol, the relation between heat of combustion at constant pressure, and heat of combustion at constant volume can be give as

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$∆ H < ∆ E$

$∆ H - ∆ E$

$∆ H > ∆ E$

None

answer is A.

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Detailed Solution

$C_{4} H_{9} {OH}_{(l)} + 6 O_{2 (g)} \to 4 {CO}_{2 (g)} + 5 H_{2} O_{(l)}$

$∆ H = ∆ E + ∆ nRT (∴ ∆ n = 4 - 6 = - 2)$

$= ∆ E - 2 RT$

$∴ ∆ H < ∆ E .$

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