In the conversion of CrO₄^-2→ Cr₂O₇^2-, the oxidation number of oxygen

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

decreases

becomes zero

increases

remains unchanged

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Explanation:

In the conversion of CrO₄²⁻ (chromate ion) to Cr₂O₇²⁻ (dichromate ion), the oxidation state of chromium changes, but the oxidation number of oxygen remains the same.

In both the chromate and dichromate ions, oxygen is bonded to chromium in the form of oxide (O²⁻), where the oxidation state of oxygen is -2. So, during the conversion from CrO₄²⁻ to Cr₂O₇²⁻, the oxygen atoms retain their oxidation number of -2.

Final Answer

The correct answer is remains unchanged.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET