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In the current carrying branch shown in the figure, the voltmeter has a resistance of $100 Ω$ .If power dissipated in $2 Ω$ ,resistance is 18 watt, the reading of the voltmeter is

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100 Volt

300 Volt

400 Volt

200 Volt

answer is D.

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Detailed Solution

$i^{2} \times 2 = 18 \Rightarrow i = 3 A$
Current through the voltmeter, $i_{v} = 3 \times (\frac{200}{100 + 200}) = 2 A$
$∴ voltmeter reading = 2 \times 100 volt = 200 volt .$

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