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In the diagram of the logic circuit, the output is represented by

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$W + (X + Y)$

$W + (X . Y)$

$W . (X + Y)$

$W . (X . Y)$

answer is B.

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Detailed Solution

$F = (W + Y) . (W + X)$
$= W . W + W . Y + X . W + X . Y (Since W . W = W)$

$= W . (1 + Y) + X . W + X . Y (Since 1 + Y = 1)$

$= W + X . W + X . Y = W (1 + X) + X . Y = W + X . Y$

$(Since 1 + X = 1)$

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