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In the diagram shown in figure, match the following columns (take $g = 10 {ms}^{- 2}$ )
Column – I Column – II
A) Acceleration of 2kg block p) 8 SI unit
B) Net force on 3kg block q) 25 SI unit
C) Normal reaction between 2kg and 1kg r) 2 SI unit
D) Normal reaction between 3kg and 2kg s) 45 N
t) None
(A) (B) (C) (D)
1) r q t p
2) r t q t
3) p t r s
4) p t q t

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answer is B.

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Detailed Solution

$\begin{array}{l} a_{Net} = \frac{F_{Net}}{M_{Net}} = \frac{60 - (18 + 6 gsin 30)}{6} = \frac{12}{6} = 2 m / s^{2} \\ on 1 kg, N_{1} - (18 + 1 gsin 30) = 1 (a) = 1 \times 2 \\ N_{1} = 25 N \\ on 3 kg, 60 - (N_{2} + 3 gsin 30) = 3 a = 3 \times 2 \\ ∴ N_{2} = 39 N \end{array}$

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