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In the diagram shown, OA is a light string of length l and a charged particle of mass m and charge Q is tied at end A. Another point charge Q is placed at B at a distance l vertically below the point O. It the particle at A is in equilibrium, tension in the string is

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2mg

$\sqrt{2} mg$

$mg / \sqrt{2}$

answer is A.

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Detailed Solution

For equilibrium of the charge at A,

F sin 45° =mg

and F cos45° = T

$∴ \frac{T}{mg} = \cot 45^{o} = 1 \Rightarrow T = mg$

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