In the diagram strings, springs and the pulley are light and ideal. The system is in equilibrium with the strings taut (T > 0), match the column. Masses are equal.

Column -1	Column -2
(A)	Just after string W breaks	(P)	aA=0
(B)	Just after spring X breaks	(Q)	aB=0
(C)	Just after string Y breaks	(R)	aC=0
(D)	Just after spring Z breaks	(S)	aB=aC

Explanation of the Problem:

The system involves two springs and several strings, with masses equal. The task is to match the conditions after different strings or springs break.

Step-by-Step Solution:

1. Understanding the System:
   • The system is in equilibrium with taut strings.
   • When a string or spring breaks, the equilibrium will be disturbed, and the accelerations of the blocks will change.
2. What happens when a string or spring breaks?
   • String W breaks:
     • If string W breaks, block B becomes unbalanced and its acceleration will be zero (aA = 0).
   • Spring X breaks:
     • If spring X breaks, the forces on block B change, resulting in its acceleration becoming zero (aB = 0).
   • String Y breaks:
     • When string Y breaks, block C loses support and its acceleration will be zero (aC = 0).
   • Spring Z breaks:
     • If spring Z breaks, blocks B and C will experience equal accelerations (aB = aC).

Final Matching:

• (A) Just after string W breaks → (Q) aB = 0
• (B) Just after spring X breaks → (R) aC = 0
• (C) Just after string Y breaks → (P) aA = 0
• (D) Just after spring Z breaks → (S) aB = aC