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Q.

In the diffraction pattern of single slit under bichromatic illumination, the first minimum with the wavelengthλ1is found to be coincident with the third maximum at λ2. So

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a

3λ1=0.3λ2

b

3λ1=λ2

c

0.3λ1=3λ2

d

λ1 =3.5λ2

answer is C.

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Detailed Solution

first minima of λ1     Sinθ1=λ1/d

third maxima of λ2    Sinθ3 = 7λ22d

λ1d=7λ22d 

λ1 =3.5 λ2

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