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Q.

In the disproportionation reaction, 3HClO₃ $\to$ HClO₄ + Cl₂ + 2O₂ + H₂O, the equivalent mass of the oxidising agent is (molar mass of HClO₃ = 84.45)

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An Intiative by Sri Chaitanya

a

28.15

b

16.89

c

32.22

d

84.45

answer is A.

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Detailed Solution

\mathop {3HCl{O_3}}\limits^{ + 5} \to \mathop {HCl{O_2}}\limits^{ + 3} + \mathop {C{l_2}}\limits^0 + 2{O_2} + {H_2}O\

It is a disproportion reaction. HClO₃ acts like both oxidant and reductant

EW of HClO₃ as oxidizing agent

\mathop {HCl{O_3}}\limits_{ + 5} \to \mathop {C{l_2}}\limits_O \

Decrease in O state = 5

EW of HClO₃ as an oxidant = $\frac{84.45}{5}$ = 16.89

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