In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available. Which of the following can be used in place of lead nitrate?

In this reaction, lead acetate can be used in place of lead nitrate because lead acetate dissociates into ${\mathrm{Pb}}^{2+}$ ions and ${\mathrm{CH}}_3{\mathrm{COO}}^{-}$ ions which will combine with I and K, respectively, to form lead iodide$\left({\mathrm{PbI}}_2\right)$ and potassium acetate$\left({\mathrm{CH}}_3\mathrm{COOK}\right)$. The reaction is given as follows:
$2\mathit{KI}+\mathit{Pb}(C{H}_3\mathit{COO}{)}_2\to \mathit{Pb}{I}_2+2C{H}_3\mathit{COOK}$