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In the electric circuit shown power dissipated in the resistor R and 2R at an instant after the switch is closed are 9W and 2W respectively. What is the rate of increase in the energy stored in the capacitor at this instant. (in watts)

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Detailed Solution

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$\frac{i_{1}^{2} R}{i_{2}^{2} 2 R} = \frac{9}{2} \Rightarrow i_{1} = 3 i_{2}$

$\frac{d v}{d t} = i_{2} (2 R) (i_{1} - i_{2}) = 4 W$

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In the electric circuit shown power dissipated in the resistor R and 2R at an instant after the switch is closed are 9W and 2W respectively. What is the rate of increase in the energy stored in the capacitor at this instant. (in watts)