In the electrochemical cell :

$\mathrm{Zn}\left|{\mathrm{ZnSO}}_4(0.01\mathrm{M})\parallel {\mathrm{CuSO}}_4(1.0\mathrm{M})\right|\mathrm{Cu}$  the emf of this Daniel cell is $E_1$. When the concentration of ${\mathrm{ZnSO}}_4$ is changed to 1.0 M and that of ${\mathrm{CuSO}}_4$changed to 0.01 M,the emf changes to ${\mathrm{E}}_2$ . From the following, which one is the relationship between ${\mathrm{E}}_1 \mathrm{and} {\mathrm{E}}_2$
(Given, RT/F = 0.059)