In the electrolytic refining of copper using ${\mathrm{CuSO}}_4$ as electrolyte, the anode reaction is

The process takes place are under. 

Anode: $\mathrm{M}\to {\mathrm{M}}^{\mathrm{n}+}+{\mathrm{ne}}^{-}$

Cathode: ${\mathrm{M}}^{\mathrm{n}+}+{\mathrm{ne}}^{-}\to \mathrm{M}$

The net result is the transfer of pure metal from the anode to the cathode.