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Q.

In the equation :

Cr2O72- + Fe2+ + H+   Cr3+ + Fe3+ + H2O

the coefficients of Fe2+ and H+  are respectively

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a

6, 7

b

6, 14

c

5, 7

d

5, 14

answer is B.

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Detailed Solution

Cr+62O7-2+ Fe+2+H+2Cr+3+Fe+3+H2O

By cross multiply the change in oxidation states,

Cr2O72- + 6Fe2+ + 14H+   2Cr3+ + 6Fe3+ + 7H2O

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