In the equilibrium $N H_{4} H S_{(s)} \Leftrightarrow N H_{3 (g)} + H_{2} S_{(g)}$ the forward reaction can be favored by

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Adding some more $H_{2} S$

Removing some $N H_{3}$ from the reaction mixture

Adding some more $N H_{3}$

Adding some more $N H_{4} H S$

answer is C.

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Detailed Solution

When some ammonia is removed from the equilibrium mixture, the equilibrium will shift to right so that more ammonia is formed which will nullify the effect of removal of ammonia.

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