In the equilibrium

$N{H}_{4}HS\iff N{H}_3\left(g\right)+H_{2}S\left(g\right)$

The forward reaction can be favored by

 The equilibrium $N{H}_{4}HS \iff N{H}_3\left(g\right)+H_{2}S\left(g\right)$ , The equilibrium will shift to the right so that more ammonia is generated, negating the benefit of removing some ammonia from the equilibrium mixture. Ammonia elimination will therefore boost the forward response.

Therefore, the correct answer is option (C) Removing some Ammonia from the

reaction mixture.