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In the estimation of halogen 0.18 g of an organic compound gave 0.12 g of silver bromide. What is the percentage of bromine in the compound? (Molar mass of AgBr = 188; Atomic weight of Br = 80)

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34.84

35.24

30.64

28.36

answer is D.

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Detailed Solution

$% of Br = \frac{80}{188} \times \frac{Wt of AgBr}{Wt . of O . C} \times 100$

$% of Br = \frac{80}{188} \times \frac{0.12}{0.18} \times 100$

$% of Br = \frac{9.6}{33.84} \times 100$

$% of Br = 28.36$

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